Error tolerance in coil design (number of turns)

AI Thread Summary
The discussion focuses on designing a coil with 2100 turns of 30AWG wire, considering the impact of heavy insulation on wire diameter. The calculated wire length is approximately 8,420 inches, but real-world variations may affect this estimate. Participants suggest allowing for error tolerance by having extra wire on hand, as precise calculations can be challenging. The choice between layer wound and random wound methods is also debated, with considerations for insulation and fill percentage. Ultimately, ensuring enough wire for the winding process is emphasized as a practical approach.
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I am designing a coil which will have 2100 turns of 30AWG wire.
The bobbin diameter is 1.045" and the length is 1.28"

From my calculations I will use about 8,420 inches of wire.
I tried an online calc but they did not take into account that the wire I am using has a heavy insulation so it's diamter is about .0115".

As we know things is the real world are usually somewhat different.

My question is how much of an error tolerance I should expect in terms of wire length for the 2100 turns? And should I expect to use more or less wire than calculated?

Any help/suggestions would be greatly appreciated.
 
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Layer wound or random wound?
If layer what is layer insulation?
If random wound, depends on winder. Assume maybe 60% fill?
 
Is this a math exercise? Like how many balls can you fit in a can?!

Just get extra wire and wind it, point is you want to have extra to make sure you have enough!
 
You could go back to the online calculator and tell it you have 26 gauge wire. This has a diameter of 0.0159 inches which is close enough to your wire with its thick insulation.

But it is an imprecise business and difficult to calculate exactly, so you do need to have some spare wire.

The main problem may be how many turns you can fit on your bobbin.
 
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