- #1
mtayab1994
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Homework Statement
Look at my work in the picture.
Homework Equations
The Attempt at a Solution
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Can someone check my work? (Finding a common divisor T)
- Thread starter mtayab1994
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Homework Help Overview
The discussion revolves around finding natural numbers T that satisfy specific divisibility conditions involving expressions derived from n, specifically T | (n^2 - n + 3) and T | (n + 1).
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants share different methods for determining values of T, with some suggesting that 1 is the only solution. Others question the completeness of the original poster's claims and the clarity of their work, particularly regarding the generality of the solution across all natural numbers n.
Discussion Status
The discussion is ongoing, with participants examining specific cases (e.g., n = 4) and debating whether the findings apply universally. There is a recognition of the need for clarity in the problem statement and the conditions under which the solutions hold.
Contextual Notes
Some participants note difficulties in reading the original post's visual content, which may affect the understanding of the problem. The focus is on the implications of the divisibility conditions rather than a definitive solution.
Look at my work in the picture.
- #2
Mark44
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Your photo is very difficult to read. Also, what is the statement you are trying to prove?mtayab1994 said:
- #3
mtayab1994
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I'm trying to find all values of natural numbers T that satisfy T l n^2-n+3 and T l n+1
- #4
mtayab1994
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Take a look at this copy and the bottom is cut off. It is S={1}
- #5
Mark44
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If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.
- #6
mtayab1994
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Mark44 said:
mtayab1994 said:
Notice that I said "If n = 4".
Here's your problem statement from post #3.
mtayab1994 said:
There's no mention of "for every n."
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- #7
mtayab1994
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Mark44 said:
Yes it divides it but not for every n.
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