Need help on another optimization problem

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The discussion focuses on maximizing the volume of an open-top box created by cutting squares from the corners of a 14-inch by 9-inch sheet. The user has derived the volume function V(x) = 4x^3 - 46x^2 + 126x and its derivative V'(x) = 12x^2 - 92x + 126 but struggles with factoring to find critical numbers. Other participants suggest using a TI-89 calculator to find the zeros of the derivative, which are approximately 5.88 and 1.79. The importance of the second derivative to determine maxima and minima is also highlighted. The conversation emphasizes the challenges of solving calculus problems without calculators during tests.
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Problem: An open top box is constructed from a sheet of material by cutting equal squares from each corner and folding up the edges. If the sheet of material measures 14 inches by 9 inches, find the dimension x which represents the length of one side of the square that should be cut off so that the volume is maximized.

Work Done (Please Check!):

Length: L(x)=-2x+14

Width: W(x)=-2x+9

Height: H(x)=x

Volume: V(x)=4x^{3}-46x^{2}+126x

This is where I am stuck:

V'(x)=12x^{2}-92x+126

I need to factor out the derivative so that I can get the critical numbers. Unless I did something wrong, from what I got above it's not going to be whole numbers. I always have problems with fractions. :redface:
 
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jzq said:
Problem: An open top box is constructed from a sheet of material by cutting equal squares from each corner and folding up the edges. If the sheet of material measures 14 inches by 9 inches, find the dimension x which represents the length of one side of the square that should be cut off so that the volume is maximized.

Work Done (Please Check!):

Length: L(x)=-2x+14

Width: W(x)=-2x+9

Height: H(x)=x

Volume: V(x)=4x^{3}-46x^{2}+126x

This is where I am stuck:

V'(x)=12x^{2}-92x+126

I need to factor out the derivative so that I can get the critical numbers. Unless I did something wrong, from what I got above it's not going to be whole numbers. I always have problems with fractions. :redface:


this is more of a calc problem than physics

get a ti89 :D

i get the zeroes as 5.88 and 1.79...if you take the 2nd derivative you can find out which is the max and which is the min...
 
Thanks for your advice and solution.

P.S. No offense, this forum deals with all subjects even though it is called Physics Forums. This is college homework so that is why I posted this here. If you look at other threads in this section, you will also find other calculus problems. And about the TI-89, I can't use calculators on tests.
 
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jzq said:
Thanks for your advice and solution.

P.S. This forum deals with all subjects. This is college homework so that is why I posted this here. If you look at other threads in this section, you will also find other calculus problems. And about the TI-89, I can't use calculators on tests.

if she gives you problems like that she better!

of course if she gives you a similar problem it will easily be factored

basically you just find the zeroes of the derivative function...either with an 89 or using factoring
 
Yea, I think it's ridiculous that we can't use calculators on tests. Fortunately, this is only a practice problem. Hopefully they won't have something like this on the test. Thanks again!
 
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