Can you help me explain how to find angular velocity?

AI Thread Summary
To find the average angular velocity from t = 0 s to t = 25 s, one must consider three distinct time intervals: acceleration, constant velocity, and deceleration. The angular velocity reaches 69 rad/s after 10 seconds of uniform acceleration, followed by 33 seconds at that constant speed. The average angular velocity calculation requires determining the rotation angle for each interval and applying the formula ωavg = Δθ/Δt. The confusion arises from only considering two intervals instead of all three, which is crucial for an accurate average. Understanding these intervals and their contributions is essential for solving the problem correctly.
mysteryowl
Messages
1
Reaction score
0
A machinist turns the power on to a grinding wheel, at rest, at time t = 0 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 69 rad/s. The wheel is run at that angular velocity for 33 s and then power is shut off. The wheel decelerates uniformly at 2.9 rad/s2 until the wheel stops. In this situation, the average angular velocity in the time interval from t = 0 s to t = 25 s is closest to:

I know that 1st there is constant acceleration, then constance velocity, and then constant deacceleration.

im really confused, the answer is 55 rad/s, but i don't know how to get the answer
 
Physics news on Phys.org
Did you draw a sketch of the angular velocity as function of t?
If you have such a sketch, how can you get the average value between two points?
 
ωavg=Δθ/Δt
ωavg=(Δθ1+Δθ2)/(Δt1+Δt2)
ωavg=[(θt=10st=0s)+(θt=25st=10s)]/[(tt=10s-tt=0s)+(tt=25s-tt=10s)]
 
Gavran said:
ωavg=Δθ/Δt
ωavg=(Δθ1+Δθ2)/(Δt1+Δt2)
ωavg=[(θt=10st=0s)+(θt=25st=10s)]/[(tt=10s-tt=0s)+(tt=25s-tt=10s)]
You did the average over just two time intervals. There are three time intervals in the problem.

Your next problem is to compute ##\Delta \theta## for each of the three intervals. What are your thoughts about the rotation angle for the first interval (the acceleration) alone?
 
It may be worth noting that the original post is over 10 years old!
 
  • Like
Likes MatinSAR and jbriggs444
Steve4Physics said:
It may be worth noting that the original post is over 10 years old!
That it is. Additional replies are unlikely to help @mysteryowl who hasn't been seen since that first post. However, it's not too late to guide @Gavran along the path to the correct answer.
 
  • Like
Likes SammyS, Steve4Physics and MatinSAR
jbriggs444 said:
You did the average over just two time intervals. There are three time intervals in the problem.

Your next problem is to compute ##\Delta \theta## for each of the three intervals. What are your thoughts about the rotation angle for the first interval (the acceleration) alone?
The task is to calculate the average velocity in the time interval from ##t=0s## to ##t=25s##. This does not include the third (deceleration) interval from ##t=10s+33s=43s## to until the wheel stops.
The rotation angle for the first interval is:
##\Delta\theta_1=\frac12\frac{\Delta\omega_1}{\Delta t_1}(\Delta t_1)^2=\frac12\Delta\omega_1\Delta t_1##
where ##\Delta\omega_1## is the angular velocity change in the first interval and ##\Delta t_1## is the duration of the first interval.
 
Back
Top