Find the area of the lune formed (Using calc please)

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Hi all,

Homework Statement


Find the area of the crescent-shaped region (called a lune) bounded by arcs of circles with radii r and R.

http://mathhelpforum.com/attachments/calculus/19696-find-area-untitled.png

Homework Equations



I know we have to use arcsin which is $$ \frac {1}{\sqrt{a^{2}-x^{2}}}$$

The Attempt at a Solution



I tried plotting the circles on a coordinate axis with the bigger circle centered at the origin and the smaller circle centered at a point (0,b) but I am not really sure where to go from here... If this was geometry, it would have been easy, but we have to use calc on this problem.

So far, i started with $$r \sqrt{R^{2}-r^{2}} +\frac{pir^{2}}{2}$$
but I am stuck now. Can anyone provide a push in the right direction for me?
Thanks in advance.
 
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anelephant09 said:
Hi all,

Homework Statement


Find the area of the crescent-shaped region (called a lune) bounded by arcs of circles with radii r and R.
http://mathhelpforum.com/attachments/calculus/19696-find-area-untitled.png

Homework Equations



I know we have to use arcsin which is $$ \frac {1}{\sqrt{a^{2}-x^{2}}}$$

The Attempt at a Solution



I tried plotting the circles on a coordinate axis with the bigger circle centered at the origin and the smaller circle centered at a point (0,b) but I am not really sure where to go from here... If this was geometry, it would have been easy, but we have to use calc on this problem.

So far, i started with $$r \sqrt{R^{2}-r^{2}} +\frac{pir^{2}}{2}$$but I am stuck now. Can anyone provide a push in the right direction for me?
Thanks in advance.
Hello anelephant09. Welcome to PF !

Your image was not visible, but I see it now.

Here it is again:
attachment.png


You need to know the separation distance between the centers of the circles .

Added in Edit:
Oh! I see from the diagram, you can figure out the separation.
 

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Last edited:
Area of circles by integration

Whoops, meant to make a new thread.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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