Period of Oscillation for a Meter Stick Suspended by a Light String

AI Thread Summary
The discussion revolves around calculating the period of oscillation for a meter stick suspended by a light string. Initial attempts using the formulas T=2pi*sqrt(L/g) and w=sqrt(g/l) were deemed incorrect. Participants noted that additional information, such as the masses of the string and meter stick, is typically necessary for accurate calculations. The instructor confirmed that the problem is solvable with the given parameters, suggesting that the alignment of the string and meter stick may be a key factor. Clarification on the setup and assumptions is essential for reaching a solution.
ness9660
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A meter stick, suspended at one end by a 0.502m long light string, is set into oscillation. Determine the period of oscillation in seconds.

At first I thought this would be a rather simple problem, so I did T=2pi*sqrt(L/g) but apparently this is very wrong.
Then I tried w=sqrt(g/l) T=(2pi)/w but this seems to be wrong as well.

But I can see no other way to do this problem using just the length and g.

Can anyone offer any insight into solving this problem?

Thanks for any help.
 
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This is a physical pendulum.U should be given the masses of the string & the meter stick,too.Something is either fishy,or is something i just don't see.

Daniel.
 
dextercioby said:
This is a physical pendulum.U should be given the masses of the string & the meter stick,too.Something is either fishy,or is something i just don't see.

Daniel.


My instructor said the problem is solvable, but yeah, all we get is the length of the string and g.
 
ness9660 said:
but apparently this is very wrong.

In what way?
 
ness,

Do you think your instructor was picturing the string and the meter stick being in line with each other. If so, I think you can solve this.
 
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