Non uniform surface charge density

AI Thread Summary
The discussion revolves around calculating the value of q for a metallic disk with a non-uniform surface charge density defined by σ=q|cosθ|*r. The user attempted to solve the problem using double integrals but encountered difficulties. A suggestion was made to treat q as a constant, referred to as C, to simplify the integration process. However, the user noted a lack of a definitive answer in their textbook, leaving uncertainty about the correctness of the approach. Clarification on the integration method and the relationship between q, Q, and R is sought to resolve the issue.
amjad-sh
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hello.
The problem is : A metallic horizontal disk of radius R has been charged on its top surface with a total charge Q such that its surface charge density is "non uniform" and governed by the expression σ=q|cosθ|*r where r and θ are the polar coordinates measured from the center O of the disk.
Determine in terms of Q and R the value of q.
I tried to solve it using double integral but it didn't work.
σ=dq/ds then dq=q|cosθ|*r*rdrdθ then ∫dq/q=0R 02∏|cosθ|dθr2dr.
If anybody can help thanks.
 
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amjad-sh said:
hello.
The problem is : A metallic horizontal disk of radius R has been charged on its top surface with a total charge Q such that its surface charge density is "non uniform" and governed by the expression σ=q|cosθ|*r where r and θ are the polar coordinates measured from the center O of the disk.
Determine in terms of Q and R the value of q.
I tried to solve it using double integral but it didn't work.
σ=dq/ds then dq=q|cosθ|*r*rdrdθ then ∫dq/q=0R 02∏|cosθ|dθr2dr.
If anybody can help thanks.
I'm very rusty on this, but consider this ...

In σ=q|cosθ|*r I think that q is fixed, so instead call it a constant, say, C.
Leading to dq=C|cosθ|*r*rdrdθ then ∫dq=C 0R 02∏|cosθ|dθr2dr.

You are solving for that constant C. If your textbook supplies the correct answer, does this get you closer?
 
I think that leads to an answer,but the problem is that there is no answer in my textbook.
so I can't be sure about the answer.
 
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