1) Let f: V x V -> F be a symmetric bilinear form on V, where F is a field.
Suppose B={v1,...,vn} is an orthogonal basis for V
This implies f(vi,vj)=0 for all i not=j
=>A=diag{a1,...,an} and we say that f is diagonalized.
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Now I don't understand the red part, i.e. how does...