Homework Statement
If f is continuous and \int^{9}_{0}f(x)dx = 4, find \int^{3}_{0}xf(x^{2})dx
Homework Equations
None required
The Attempt at a Solution
Don't really know where to begin, but I tried:
for \int^{3}_{0}xf(x^{2})dx
let:
u = x^{2}
du = 2xdx
substitute...
Hi, am I on the right track with this U-substitution problem?
Homework Statement
Evaluate the indefinite integral
Homework Equations
integral of x^2(x^3 + 5)^9 dx
The Attempt at a Solution
integral of x^2(x^3 + 5)^9 dx
Let u = x^3 + 5
du = 2x^2
1/2du = x^2
1/2 integral u^9 du
1/2...
Homework Statement
Question is:Integrate x(2x+1)^8 dx in terms of x.
Homework Equations
The Attempt at a Solution
Here is how i started off:by relabeling them.
let u = 2x+1. du/dx = 2.
dx=du/2.
Also x=u-1/2.
So my terms now are: Integral (u-1/2)u^8 (du/2) <- this is where i...
Homework Statement
2
h(x)=∫√(1+t^3) dt find h'(2)
x^2
Homework Equations
The Attempt at a Solution
I started out solving this equation by flipping x^2 and 2 and making the integral negative. From here on out, I'm lost. I've tried substituting u in for 1+t^3 and solving...
Homework Statement
Compute the indefinite integral.
∫(x^2 + 1)^(-5/2) dx
The Attempt at a Solution
I have a hunch that I need to substitute x = tan(u) but, as always, my lack of trig skills are holding me back.
Homework Statement
\int sin^{5}x cosx dx
Homework Equations
None
The Attempt at a Solution
I tried setting u=sin^5(x) but this ended up yielding \frac{1}{5}\int u cos^{3}x du and I cannot think of a better substitution. Any tips?
Homework Statement
Integrate \int\frac{dz}{1+e^z} by substitution
Homework Equations
The Attempt at a Solution
I chose u=(1+e^{z}) so du/dz=e^{z} and dz=du/e^{z}.
Therefore, \int\frac{1}{u} \frac{du}{e^{z}}
I plug z=ln(u-1) in for z, so \int\frac{1}{u} \frac{du}{u-1}...
Homework Statement
I was asked to find the formula for the antiderivative \int1/(25+x^{2})
Homework Equations
Take a 'part' of the equation and use it to solve the antiderivative, integration by substitution.
and dw=(1/5)dx
The Attempt at a Solution
I initially set my substitution...
Homework Statement
I've come across the problem
\ \int x(x^{2}+5)^{75} dx
Homework Equations
The Attempt at a Solution
Once going through the whole problem I got \ \frac{(x^{2}+5)^{76}}{76}+c
but the text I have said the answer was, \frac{1}{152}(x^{2}+5)^{76}+c.
What did I do...
Homework Statement
I have the function below which i need to find the area under the graph.
Homework Equations
\int_{ - \frac {\pi}{4}}^{\frac {\pi}{3}}\frac {2\sec x}{2 + \tan x}dx
The Attempt at a Solution
I can simplify it to
\int_{ - \frac {\pi}{4}}^{\frac {\pi}{3}}\frac {2}{2\cos x +...
Homework Statement
Use substitution to evaluate the integral.
\int \frac{4cos(t)}{(2+sin(t))^2}dt Homework Equations
None, really.The Attempt at a Solution
I'm not sure what to use as u, for the substitution. I've tried (2+sin(t))^2, as well as other attempts, but I can't seem to find anything.
Homework Statement
It's been god knows how long since I've had to use integration by substitution. I've totally forgotten it. I am trying to integrate to solve for the value of an electric field at a given point. The integral I am trying to solve is...
I just learned how to integrate through substitution and I was challenged by my teacher with an apparently easy problem but I'm really struggling with it.
He said he will give me an F if I don't solve it for tomorrow, I guess this is what I get by being the one who always understand in class...
Homework Statement
Evaluate the definate integral of the following
\int (from 1 to 2) \frac{sin t}{t} dt
The Attempt at a Solution
I am actually stuch from the very beginning.
I tried to set u=sin(t) but this doesn't help much because (sint)'=cost and
this is going to make the...
Hello all, how are you?
we are currently working on integration by substitution, what do you guys think about the way i solved this one:
Find: \int \frac{(t+1)^2}{t^2} dt
My solution:
\int \frac{(t+1)^2}{t^2} dt
= \int 1dt + \int \frac{2}{t} dt + \int \frac{1}{t^2} dt
= t +...
Homework Statement
I want to integrate (1+x)/(1-x)
Homework Equations
The Attempt at a Solution
I have looked at many examples of substitution method - this one appears simple but I am not finishing the last step...
- I know you must first take u=(1-x)
- Then du = -dx
what...
1. Find, by substitution, the integral of; 3x2(x3 - 2)4 dx
2. susbt'
3. u = x3 - 2, so du/dx = 3x2, and du = 3x2 dx
Now this is where I'm not sure what to do. As u = x3 - 2 you know that x = (u + 3)1/3, and so i think you can write the integral as;
\int(u+3)1/3.u4 du ... but i when i look...
Hi all,
I've been studying calculus out of Tom Apostol's book "Calculus". I'm having troube with the following problem in the section on integration by substitution:
Integrate \int(x^2+1)^{-3/2}\,dx.
I tried the substitution u=x^2+1 but it didn't seem to work. I can't see anything else...
Question:
\int^{1}_{-1} \frac{dx}{(1+x^4)}
I attempt:
u = x^2,
so x= u^1/2
dx= 1/2 u^(-1/2)
Which gives me \int^{1}_{1} \frac{1}{(1+x^4)} * \frac{1}{(2u^1/2)}du, which is 0. Thats not the answer as seen by any graphing utility.
Where is this error? I do not know integration by parts. I just...
the problem asks for the area under the shaded region of the line y = 1/(1-x^2) on the interval [-1,1].
so far I've set up the integral showing
\int [tex]dx/(1-x^2)[\tex]
on the interval [-1,1]
i'm pretty sure you have to use substitution to solve it, but i can't seem to figure it out...
How was Integration by Substitution and Trig Substitution developed? My calc book doesn't have much info, just a short (not really complete) proof. Could someone explain and/or lead me in the right direction?
Homework Statement
Homework Equations
None. Well, dx=du/cosx
The Attempt at a Solution
I've substituted it in, got new values for the limits but I have u^-1 on the bottom and so can't integrate it from my current knowledge. Basically I'm stuck with:
Integration of u^(-1) du...
Homework Statement
Find by letting U^2=(4 + x^2) the following \int_0^2\frac{x}{\sqrt{4 + x^2}}dx?
I can solve it by letting \mbox{x=2} tan(\theta), But I want to be able to do it by substitution.
The Attempt at a Solution...
Homework Statement
Solve the differential equation.
dy/dx = 4x + 4x/square root of (16-x^2)
Homework Equations
Substituting using U...
The Attempt at a Solution
I'm not sure if that's what I am supposed to do, but I tried using the U substitution...
4x + 4x/square root of...
I did a few problems in integration by parts. There are two that I just can't seem to get. I've tried every type of subsitution or part I can think of.
1. e^sqrt(x)
2. sin (ln x)
Hello,
evaluate the following integral:
\int x \sqrt{x^2+a^2}dx
definite integral from 0 to a
what I did was
u = x^2 + a^2
du = 2xdx
1/2 sqrt(u)du
I just dropped the a^2 because we were finding the derivative of x but feel that it's very wrong.Any suggestions are much appreciated.
thanks.
evaluat the indefinite integral ((sin(x))/(1+cos^2(x)))dx
I let
u = 1 + cos^2(x)
then du = -sin^2(x)dx
I rewrite the integral to
- integral sqrt(du)/u
can I set it up like this? should I change u to something else?
I also tried it like this by rewriting the original equation...
Definite integration by substitution
I just need a check on this, the book and I are getting different answers...
The problem and my answer:
http://www.mcschell.com/p14.gif
http://www.mcschell.com/p14_worked.jpg
The book gives 0.00448438 though. :confused:
Thanks!
-GeoMike-
I am going crazy on this problem:
\int sec(v+(\pi/2)) tan(v+\pi/2)) dv
if I substitute u= tan(v+\pi/2)) dv , can I use the product rule to find du= sec(v+(\pi/2)) dv .
Thanks, Todd
I'm stuck on how to advance further on this problem and if anyone can point my in the right direction I would be greatly appreciative.
\int\frac{dx}{\sqrt{x(1-x)}}
The integral has to be solved using substitution, but we are required to use
u=\sqrt{x}
From this...
Integration by substitution...
Accroding to my notes, when performing integration by substitution, du/dx= f'(x), and therefore du = f'(x)*dx. But how is this possible? We are treatnig dy/dx as if it were a fraction - but in essence it is not! So why is this statement still true?
Thanks. :smile:
Please help. I'm having trouble with a simple integration by substitution problem
The integrand is f(x) = x* sqr(x-1)
The interval [1,2]
Please draw it out in a gif file and send it to me via email.
-much appreciated.
For our homework this week for Pure, one of the questions is to ingration 1/(16 + x^2) with respect to x between the limits 0 and 4. I know the result from the formula wqith arctan in it, but since we've to use substitituion here and not just plonk down the formula, I'm confused as to what to...