1. The problem statement, all variables and given/known data 2 h(x)=∫√(1+t^3) dt find h'(2) x^2 2. Relevant equations 3. The attempt at a solution I started out solving this equation by flipping x^2 and 2 and making the integral negative. From here on out, I'm lost. I've tried substituting u in for 1+t^3 and solving it that way, but I get caught up when I get du=3t^2 dt and h(x)=∫u^(1/2) du/(3t^2). How am I supposed to compensate for a t variable in the denominator? I can handle the rest of the problem if I can just find the antiderivative of √(1+t^3).