Hello,
I understand that if we have three functions f, g, and h, they are linearly independent <=> the only c1, c2, and c3 that satisfy (c1)f+(c2)g+(c3)h=0 are c1=c2=c3=0.
In order to solve for these c1, c2, and c3, we want three equations in the three unknowns. To do this we can...