15th derivative of a binomial/maclaurin series

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Homework Statement



sqrt(1+x^4)

use the binomial series to find the maclaurin series for the above function. then use that to find the 15th derivative at 0.


Homework Equations



-binomial series


The Attempt at a Solution



I've gotten to:

\Sigma (k n) (x^(4n))
from n=0 to infinity

How can i use this to find derivatives?
 
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i haven't checked what you've got to...

but if you write out the form for a maclaurin series in terms of its dereivatives, fror ecach term, notice the power of x & the order derivative in the coefficient are always the same
 
f(x) = f(0) + \frac{f'(0)}{1!}x+\frac{f^''(0)}{2!}x^2+..+\frac{f^{n}(0)}{n!}x^n+..

f(x) = f(0) + \frac{f^{1}(0)}{1!}x^1+\frac{f^{2}(0)}{2!}x^2+..+\frac{f^{n}(0)}{n!}x^n+..
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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