Calculating Molecule Speed Ratios in a Gas Mixture

AI Thread Summary
The discussion focuses on calculating the root mean square (rms) speed ratio of oxygen to nitrogen molecules in a gas mixture, using their molar masses of 32 g/mol for oxygen and 28 g/mol for nitrogen. The key equation used is derived from the kinetic theory of gases, relating the rms speed to temperature and molar mass. The participant initially struggles with manipulating the equations due to the differing masses but ultimately finds the ratio to be approximately 0.935. Additionally, the second question addresses how the rms speed of neon molecules increases if the temperature is quadrupled, indicating a direct relationship between temperature and molecular speed. The conversation highlights the application of fundamental physics principles in solving gas mixture problems.
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Homework Statement


1) A container is filled with a mixture of nitrogen and oxygen. What is the ratio of the rms speed of oxygen molecules to that of a notrigen molecules? (molar mass of oxygen = 32 g/mol; molar mass of nitrogen = 28 g/mol)

2) By what factor does the rms speed of neon molecules increase if their temperature increased by a factor of 4?

Homework Equations



rms= squared, mean, root.

1/2mv²=3/2KT where K = 1.83 x 10^-23 (Boltzmann's constant)
average velocity vectors of molecules = 0

The Attempt at a Solution



I'm completely clueless as to how to answer this question.
 
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(1/2)*m_O*v_O^2=(1/2)*m_N*v_N^2=(3/2)*k*T. Manipulate this to get a ratio of v_O to v_N. I.e. solve for v_O/v_N. Relatively the same approach for 2).
 
I don't see how you can get rid of the masses and the other variables if they're not constants. The instructions give the molar masses of the gases which are obviously not the same. So, we can't cancel them out when manipulating the equations. May I ask what do you get as an answer?
 
If I divide one expression by the other I get (m_O/m_N)*(v_O/v_N)^2=1. Does that help you to see where to go?
 
Oh I see thank you, I got it. 0.935 :).
 
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