Electric Field Between/Above Parallel Charged Rods

AI Thread Summary
The discussion focuses on calculating the electric field between and above two parallel charged rods with linear charge densities of +lambda and -lambda. It clarifies that the electric field is not zero above the rods, contrary to initial assumptions, and emphasizes the need to consider the fields produced by each rod. The approach for calculating the electric field between the rods involves integrating the contributions from each rod, leading to a formula that accounts for their combined effects. For points above the rods, the vector sum of the fields must be taken into account, and the behavior of the field at large distances is also discussed. Understanding these principles is crucial for solving the problem accurately.
Fusilli_Jerry89
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Homework Statement


2 uniformly charged very long (L -> infinite) straight, parallel rods d cm apart each carry a linear charge density +lambda and -lambda.
Find the magnitude and direction of the electric field between the 2 rods (x=0, -d/2 < z < d/2) and above the rods (x=0, z > d/2)


________________________________

---------------------------------------------->x
________________________________ (z is vertical axis)

Homework Equations



E = q/4(pi)(epsilon)(r^2)

The Attempt at a Solution


First of all, would E be zero above the 2 rods? The question also has a b part to it that asks what the behavior is if z is much greater than d. I guessed that E was not zero above the 2 rods since it seemed like there were so many marks for finding E above the rods, but was I wrong? If not, do you calculate E above the rods the pretty much the same way as below only subtract them instead of add them?

For E between the rods:
dE = q/4(pi)(epsilon)(x^2 + (d^2)/4)
cos(theta) = (d/2)/(x^2 + (d^2)/4)^.5
dEz = qd/8(pi)(epsilon)(x^2 + (d^2)/4)^3/2

Ez = [qd/8(pi)(epsilon)] * integral from -L/2 to L/2 of (x^2 + (d^2)/4)^-3/2 dx
Ez = qL/2(pi)(epsilon)d
since there are two rods, we multiply this by 2:
E = qL/(pi)(epsilon)d

is this method/approach correct? Thx
 
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Fusilli_Jerry89 said:

The Attempt at a Solution


First of all, would E be zero above the 2 rods? The question also has a b part to it that asks what the behavior is if z is much greater than d. I guessed that E was not zero above the 2 rods since it seemed like there were so many marks for finding E above the rods, but was I wrong? If not, do you calculate E above the rods the pretty much the same way as below only subtract them instead of add them?

E would not be zero above the rods -- that happens with infinite planes.

You have to know the field of an infinite wire at a dist r. This is done in all the books, so I'll just give it here:

\frac{1}{4\pi\epsilon_{0}} \frac{2\lambda}{r}.

The direction of the field is obvious.

You have to take the vector sum of the fields due to the two rods. In this case, since both the fields are in the same line, just adding or subtracting will do. To find it at a large distance, take the limit of z tending to infinity.

If you look at the two rods from a great distance, how do you feel it should look like?
 
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