2 complex roots 2nd ODE, did I mess up finding a constant?

mr_coffee
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It is me again, 2 problems later I ran into another problem, I've submitted it a few different times but still is incorrect. Anyone see my mistake? I entered this as the answer:
http://cwcsrv11.cwc.psu.edu/webwork2_files/tmp/equations/a0/13092fac04d4a01ec22b57e193ed051.png

Here is the problem:
Find y as a function of t if
81y'' + 126y' + 79y = 0,
y(0) = 2, y'(0) = 9 .
y =

Here is my work:
http://img132.imageshack.us/img132/9167/lastscan5tu.jpg

Any help would be fantastical.
:biggrin:
 
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Hmm...I got B=\frac{95}{\sqrt{30}} but I could have made a mistake. I think there is a mistake in your differentiation. Check it again. I can see that you have multiplied in the 7 coming from differentiation of the exponential, but what happened to the 9? Remember that \frac{d}{dt}e^{-\frac{7}{9}t}=-\frac{7}{9}e^{-\frac{7}{9}t}.
 
I find that working through a problem twice is usually a good way to catch arithmetic errors. Unless you are suffering from a systematic misunderstanding, you will usually not make the same mistake twice.
 
Ahh yes, i did it again and got the same answer as you did assyrian, thanks a ton! http://cwcsrv11.cwc.psu.edu/webwork2_files/tmp/equations/bb/6a9d9ea040028c2ece7c021178bc261.png
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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