2 objects from the same altitude?

  • Thread starter Thread starter egerol1
  • Start date Start date
  • Tags Tags
    Altitude
AI Thread Summary
Two objects of different masses but the same shape, when dropped from the same altitude, will not land at the same time if air resistance is considered. At terminal velocity, both objects experience a balance of forces, but their gravitational forces differ due to their masses. The net force and resulting acceleration will vary for each object because air resistance affects them differently. While both objects reach terminal velocity, the heavier object will have a higher terminal velocity, leading to different fall times. Therefore, under the influence of air resistance, the two objects will not land simultaneously.
egerol1
Messages
5
Reaction score
0
Hello my question is this:

If we throw 2 objects which are same but their masses are different from the same altitude they drop to the land in the same time?

(We consider that the friction force is active it's not negligible
 
Physics news on Phys.org
egerol1 said:
Hello my question is this:

If we throw 2 objects which are same but their masses are different from the same altitude they drop to the land in the same time?

(We consider that the friction force is active it's not negligible

Suppose that the drop altitude was high enough that both objects could each terminal velocity for a good portion of their falls. At terminal velocity a body is no longer accelerating. Draw the free body diagram for each. How do the forces add up? Is the terminal velocity the same for each?
 
egerol1 said:
Hello my question is this:

If we throw 2 objects which are same but their masses are different from the same altitude they drop to the land in the same time?

(We consider that the friction force is active it's not negligible

You appear to be saying the two objects have the same shape, so the friction force is the same for both. In which case they do land at the same time.
 
AC130Nav said:
You appear to be saying the two objects have the same shape, so the friction force is the same for both. In which case they do land at the same time.

No, they won't. Write the equation for forces acting and the resulting acceleration. Here's a hint: In the case where no air resistance is acting, the force due to gravity is F = m*g. The acceleration is then given by Newton's second law, so a = F/m, or a = m*g/m = g. All fine and dandy, and just what is expected: everything falls with acceleration g.

Now try the same thing only let air resistance play a part in determining the net force. Just assume that the air resistance is given by some arbitrary function, f(v). How does the result vary with mass?
 
AC130Nav said:
You appear to be saying the two objects have the same shape, so the friction force is the same for both. In which case they do land at the same time.

But the gravitational force is different. :redface:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top