2 story problems for algebra 2/trig

  • Thread starter Thread starter shemer77
  • Start date Start date
  • Tags Tags
    Algebra
AI Thread Summary
The discussion revolves around two algebraic problems: the motion of a ball and the dimensions of a rectangular garden. For the first problem, the equation h = -16t^2 + 80t is set to 64 to find the time interval when the ball is above 64 feet, leading to two solutions, t = 1 and t = 4 seconds, which represent the times when the ball is at that height. The second problem requires setting up a quadratic equation based on the perimeter and area of the garden, leading to the equation y^2 - 30y - 209 = 0 after correcting a sign error. Participants clarify the physical meaning of the solutions and confirm the setup for both problems. Understanding these concepts is essential for solving the given algebraic problems effectively.
shemer77
Messages
96
Reaction score
0

Homework Statement


1) A ball is thrown straight up with an initial velocity of 80 ft/s. Using the formula h=-16t^2 + 80t, determine the interval of time in which the ball is at least 64 feet above the ground?
2) The perimeter of a rectangular garden is 60ft. The area of the garden is 209 ft^2. Set up and solve a quadratic equation to determine the dimensions of the garden

For number 1 do i just do 64=-16t^2 + 80t?
 
Physics news on Phys.org
Those are fun problems. Neither of them rely on Trigonometry (referring to "algebr 2/trig" in your subject name). Your #2 needs two variables, maybe like x and y for the two dimensions of the reactangle. x+x+y+y=60 and x*y=209. DO IT!
 
shemer77 said:

Homework Statement


1) A ball is thrown straight up with an initial velocity of 80 ft/s. Using the formula h=-16t^2 + 80t, determine the interval of time in which the ball is at least 64 feet above the ground?
2) The perimeter of a rectangular garden is 60ft. The area of the garden is 209 ft^2. Set up and solve a quadratic equation to determine the dimensions of the garden

For number 1 do i just do 64=-16t^2 + 80t?
That's the first step. Of course, since that is a quadratic equation you can expect to get 2 solutions- and the problem asks for the "interval of time in which the ball is at least 64 feet above the ground". What do the two solutions to that quadratic equation represent physically?
 
1) I got 4 and 1, how is that possible?
2)I got y^2-30y-209=0 as my quadratic equation is that right?
 
shemer77 said:
1) I got 4 and 1, how is that possible?
2)I got y^2-30y-209=0 as my quadratic equation is that right?

No. You made a sign error. You want for #2, y^2-30y+209=0,
Then you are ready to finish the solution.
 
thanks, what about number 1?
 
Well do you understand what hallsofivy said? From the quadratic you concluded that the solution is x=1 and x=4. Do you know what these numbers actually represent physically for the ball in motion?
 
Back
Top