2D kinematics - conveyer belt question

AI Thread Summary
The problem involves sand moving at a constant speed of 6.0 m/s down a conveyor belt tilted at 15°. To solve for the horizontal distance to the pipe located 3.0 m below the conveyor belt, the x and y components of the sand's velocity must be calculated immediately after it leaves the belt. The horizontal component can be derived using the cosine of the angle, while the vertical component uses the sine. The kinematics of projectile motion will apply once the sand exits the conveyor belt, allowing for the determination of the distance to the pipe. The solution requires applying these principles to find the required horizontal distance.
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Homework Statement


Sand moves without slipping at 6.0m/s down a conveyer belt that is tilted 15°. The sand enters a pipe 3.0m below the end of the conveyer belt. What is the horizontal distance between the conveyer belt and the pipe?


Not sure where to start.
 
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You don't have to worry about any acceleration while the sand is on the conveyor belt because it tells you it moves 6 m/s the whole way down. The kinematics problem really starts the instant the sand leaves the conveyor belt. You can start by finding the x and y components of velocity of the sand right after leaving the conveyor belt.
 
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