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## Homework Statement

The position vector of a particle is given by r= ihat(2t^3-21t^2+60t+10) +jhat(3/2)(t^2-10t+9)

At what time, if any, is the velocity of the particle zero (ie what time is the particle instantaneously at rest)

## Homework Equations

## The Attempt at a Solution

Finding the velocity vector is simple, just taking the derivative of position

However, when I set that to 0 I have the ihat and the jhat and I don't know how to combine them to solve for the time. Is this even the right step?

If I take

v= (6t^2-42t+60)ihat+(3t^2-15)jhat

and set that to 0

how do I account for the vx and vy when setting that to 0?

Do I set vx and vy to 0 separately?

I'm really confused.

Thanks.