You have 3 masses. M1 = 4 kg. M2 = 1kg. M3 = 2kg, M1 is attached to M2 by a rope. M2 is attached to M3 by a rope. M1 is hanging from a pulley attached to the left end of a table, M2 is on the table, and M3 is hanging from a pulley attaced to the right end of the table.
The coefficient of friction for the table is 0.48
Find the downward acceleration of M1, the leftward acceleration of M2 and the upward acceleration of M3.
Also find the Tensions of the left rope(the one attaching M1 and M2) and the right rope(the one attaching M2 and M3)
- Acceleration for M1, M2 and M3 are the same, right?
- The masses are moving, therefore the net force /= 0, right?
Ff = mu k * FN
F = ma
The Attempt at a Solution
I dont understand this at all.
Ff = (0.48) (9.8) (1kg) = 4.704
FnetM1 = 19.6 - 4.704 = 15.096 N (to the left).
Acceleration = 15.096 / mass(1kg) = 15.1 m/2
This is wrong. I cant figure anything out...for Gods sake someone please help me.