Why Do People Put Their Ears to Railroad Tracks to Detect Approaching Trains?

AI Thread Summary
Placing ears on railroad tracks allows individuals to detect approaching trains due to the efficient transmission of sound waves through metal. Sound travels faster and farther in solid materials like steel compared to air, making it easier to hear distant trains. The vibrations from the train create disturbances in the track, which can be detected more effectively than through air. This method provides an early warning system, enhancing safety for those near the tracks. Understanding the properties of sound in different mediums highlights the advantages of using metal for sound detection.
m.l.
Messages
5
Reaction score
0

Homework Statement


People put their ears to a railroad track to get an early warning of an approaching train. why did this work.


Homework Equations


written response.


The Attempt at a Solution


Sound waves can travel a long way along an undisturbed metal rod?
 
Physics news on Phys.org
The rod has to be disturbed for any sound to be carried along it. Apart from traveling a long way in the rail, what other property does sound have in the metal that is greater than in air that would be an advantage?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top