How Do You Calculate Outcomes and Measures in a Binomial Distribution?

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In a binomial distribution B(3, 0.5), there are two outcomes for each trial: success or failure. The number of trials is three, as indicated by the parameter n. The variable can take on four possible values, ranging from 0 to 3 successes. The mean of this distribution is calculated as n * p, which equals 1.5, while the standard deviation is found using the formula √(n * p * (1-p)), resulting in approximately 0.87. Understanding these fundamentals is essential for calculating outcomes and measures in a binomial distribution.
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hello,
please i'm, taking statistic this term and i really have a problem with this question:
which is
for the distribution B(3,0.5),
a) how many outcomes are there to each trial?
b) how many trials are there?
c) how many possible values can the variable take?
d) what are the mean and standard daviations of this distribution?
please help me. if you can't just tell me who can help me ?
please
i'm beggining you
thanks alot
jody
 
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I assume you are talking about a binomial distribuition for n=3 and p=.5? Think about what a binomial distribution is. It counts the number of sucesses in n independent bernoulli trials that have sucess with probability p, right?

a) Well, what are the outcomes of a bernoulli trial?
b) Well, what is n?
c) Think about the sample space, how many possible successes can you get in n trials?
d)Well, the mean is the expectation and the SD is the root of the variance.

That should get you started.
 

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