hiuting
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Homework Statement
The A-string (440Hz) on a piano is 38.9cm long and is clamped tightly at both ends. If the string is under 667-N tension, what is its mass?
Homework Equations
\lambda = vT
\mu = mass/length
v = \sqrt{F/\mu}
The Attempt at a Solution
I don't really know which equations to useI don't know if it's right
For fundamental harmonics, L = \lambda/2
so 0.389m = \lambda/2
\lambda = 0.778m
\lambda = vT
0.778 = \sqrt{F/\mu} (1/440Hz)
0.778 = \sqrt{667/\mu} (1/440Hz)
\mu = 0.00569 = mass / 0.389m
mass = 0.0022kg
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