Solving Nonideal Voltmeters with R_V, r, and E

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The discussion focuses on calculating the potential difference measured by a voltmeter connected to a battery with internal resistance. The user initially struggles with two equations involving the battery's emf, internal resistance, and voltmeter resistance. They successfully solve for the voltmeter reading but then encounter a new challenge regarding the minimum resistance required for accurate readings within 1.0% of the emf. The user ultimately resolves this issue as well, indicating they no longer need assistance. The thread concludes with the user expressing satisfaction in solving their problems.
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Here is the question, for reference:

A voltmeter with resistance R_V is connected across the terminals of a battery of emf E and internal resistance r. Find the potential difference Vmeter measured by the voltmeter.
Express your answer in terms of R_V, r, and E.

I have two equations but am having trouble solving them for V, clearly by eliminating I

E-(I*r)-(I*R_V)=0
V_ab=E-(I*R)

Any help would be appreciated, thanks.
 
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Nevermind, I got it, but the next problem is giving me a bit of trouble:

If E = 7.5 volts and r = .45 ohms, find the minimum value of the voltmeter resistance R_V for which the voltmeter reading is within 1.0% of the emf of the battery.

I am given the following equation to work with:

E(1-(r/(r+R_V))
 
Nevermind, got that too. Disregard this thread, heh.
 
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