A 100-g piece of metal initially at T = 75oC

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To find the final temperature of a 100-g piece of metal at 75°C submerged in 100 g of water at 25°C, the equation q=mc(delta T) is used for both substances. The specific heat capacities are 0.45 J g-1 °C-1 for iron and 4.18 J g-1 °C-1 for water. A user attempted to solve the problem by equating the heat lost by the metal to the heat gained by the water but encountered calculation errors. Assistance was requested to identify the mistakes in the calculations. The discussion emphasizes the importance of correctly applying the heat transfer equation to solve for the final temperature.
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Homework Statement


A 100-g piece of metal initially at T = 75oC is submerged in 100 g of water initially at T = 25oC. The specific heat capacity of iron is 0.45 J g-1 °C-1 and the specific heat capacity of water is 4.18 J g-1 °C-1. What is the final temperature of both substances in oC?


Homework Equations


q=mc(delta T)


The Attempt at a Solution


well i tried to set mc(delta T)=mc(delta T), plug in all the values and solve for T(final), but i keep getting the wrong answer
 
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Can you show your work? It is hard to see what your problem is without being able to check your calculations.
 
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