A ball is thrown straight up from ground level

AI Thread Summary
A ball is thrown straight up from ground level and reaches a height of 136.1 m after 6.1 seconds, with gravity at 9.8 m/s². The equation used to solve for initial speed is Δx = Vi*t + 1/2*a*t². Participants emphasize the need to correctly apply the equation to find the initial velocity (Vi). Clarifications are requested regarding the completion of the equation and the calculation process. The discussion focuses on ensuring the proper application of kinematic equations to solve the problem accurately.
Emely
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A ball is thrown straight up from ground level. After a time 6.1 s, it passes a height of 136.1 m. What was its initial speed? The accelera-
tion due to gravity is 9.8 m/s2 . Answer in units of m/s.

Homework Equations

The Attempt at a Solution

 
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Please show your attempt at the problem (forum rules).
 
Emely said:
A ball is thrown straight up from ground level. After a time 6.1 s, it passes a height of 136.1 m. What was its initial speed? The accelera-
tion due to gravity is 9.8 m/s2 . Answer in units of m/s.

Homework Equations

The Attempt at a Solution

Delta x= 136.1
T=6.1
A=9.8
Vi*t+1/2at^2
 
CWatters said:
Please show your attempt at the problem (forum rules).
I did it
 
Emely said:
Delta x= 136.1
T=6.1
A=9.8
Vi*t+1/2at^2

That last equation is incomplete.

Vi*t+1/2at^2 = ?
 

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