A couple of projectile trajectory-related questions

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The discussion revolves around determining the angle at which the horizontal and vertical components of a vector are equal in magnitude. The correct answer is identified as 45 degrees, as this angle creates two congruent angles in a right triangle, each measuring 45 degrees. The participant confirms their reasoning by drawing a right triangle and noting that the angles must sum to 90 degrees. The conversation suggests that further questions should be posted separately for clarity. The focus remains on understanding vector components in projectile motion.
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First one (to check with others on whether or not it's correct, although I'm sure it's very easy)

Homework Statement


A vector makes an angle, theta, with the horizontal. The horizontal and vertical components of the vector will be equal in magnitude if angle theta is
Four Choices
(1) 30 degrees
(2) 45 degrees
(3) 60 degrees
(4) 90 degrees

Homework Equations


None I believe

The Attempt at a Solution


1. I drew out a right triangle
2. Angle theta is located at the left portion of the right triangle
3. Right angle = 90 degrees, of course
4. Two congruent angles will have congruent sides; as a result, 45 degrees is my answer (also because the two angles have to be equal and must add up to 90).

I'll add another one in a bit after I get this out of the way.
 
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correct. If you have additional questions, you might want to start a new post.
 

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