A couple of questions regarding AREAS (and getting the formulas,etc.)

[mathzeroh]

Same thing I did! (just different variables)

exactly.

 

[dextercioby]

Okay guys the total LENGTH OF THE WIRE/FENCE NEEDS TO BE 80,REMEMBER?

Take the rectangle from the right (similar with the one in the first problem).The total legth available is 80-(10-3)=73 ft...

The area function is
S(x)=x(73-x)

which gives a maximum area of 666.125ft squared.

If u add the rectangle which has fence only on one out of the 4 sides,the total area becomes 921.625.

Daniel.

 

[dextercioby]

NOTE:There's no fence along the 10 feet side,simply because the bolded line/contiur does not include that portion...

Daniel.

 

[mathzeroh]

true. But this is what i did:

there were three 3 sides to be dealt with:

y-3
y-10
x

these. (and maybe christinono used the same thing except switched the variables).

so this is what i did, i put the ys together:

y-3+y-10

put the like terms together:

2y-13

and that's how i went forward with it...is that right?

 

[christinono]

Okay guys the total LENGTH OF THE WIRE/FENCE NEEDS TO BE 80,REMEMBER?

Take the rectangle from the right (similar with the one in the first problem).The total legth available is 80-(10-3)=73 ft...

The area function is
S(x)=x(73-x)

which gives a maximum area of 666.125ft squared.

If u add the rectangle which has fence only on one out of the 4 sides,the total area becomes 921.625.

Daniel.

Daniel, I don't agree. We are looking for the area of the WHOLE garden, not just the area enclosed by the fence. When I said that:
80 = (x-10) + (x-3) + y, I was saying the total length of the fence was 80 ft. What was represented by "x" was the total bottom side (same as the top), not just the length of the wire on the bottom.

 

[dextercioby]

No.You should add:
10-3+y+2x=80

And the total area is y(x+7).

Daniel.

 

[christinono]

No.You should add:
10-3+y+2x=80

And the total area is y(x+7).

Daniel.

I don't understand what you mean or what is wrong with how we solved the problem.

 

[christinono]

Daniel, could you define what "x" is in your equation?

 

[dextercioby]

Daniel, I don't agree. We are looking for the area of the WHOLE garden, not just the area enclosed by the fence.

The fence does not inclose an area,because it's not an enclosed curve...

80 = (x-10) + (x-3) + y, I was saying the total length of the fence was 80 ft. What was represented by "x" was the total bottom side (same as the top), not just the length of the wire on the bottom.

Yes,we're not talking about the same area...

This problem is confusing...

Daniel.

 

[dextercioby]

Daniel, could you define what "x" is in your equation?

"x" is the length of the part of the fence which is left "outside" to form the exterior rectangle...

Daniel.

 

[christinono]

You're right, it's confusing. I think that by "area", they mean the area of the whole garden. In that case, it would be 1081.125 sq. ft.

 

[dextercioby]

Okay,have it your way.It's not like I've lost something...

Daniel.

 

[mathzeroh]

Think of it like this fellas:

 

[dextercioby]

It's not the only way to think of this problem...


Daniel.

 

[mathzeroh]

It's not the only way to think of this problem...


Daniel.

No argument there. this is math, math is infinite...sometimes.

 

[christinono]

I think it's the way the textbook and the teacher want us too.

 

[dextercioby]

I think it's the way the textbook and the teacher want us too.

Did u talk to them...??How would you know what the teacher thinks...? Did u ask the book...??

Daniel.

 

[christinono]

didn't you know, I'm psychic!
No, judging by the complexity of the first 3 problems, I'm assuming that's what they meant.