- #1
nyclio
- 14
- 1
I recently had a physics test and here are the questions that were given. I answered 3 out of 4. Would an expert please be able to tell me if I got them right or if not, please lead me in the right direction? I would wait to get my test back but that won't be for another 2 weeks and I am curious. Thanks in advance. :)
A 0.20 kilogram mass is sliding on a horizontal, frictionless air track with a speed of 3.0 meters per second when it instantaneously hits and sticks to a 1.3 kilogram mass initially at rest on the track. The 1.3 kilogram mass is connected to one end of a massless spring, which has a spring constant of 100 Newtons per meter. The other end of the spring is fixed.
A) Determine the following for the 0.20 kilogram mass immediately BEFORE the impact.
1. Its linear momentum:
p=mv
= (0.20)(3)
=0.6 kg*m/s
2. It's kinetic energy:
KE=0.5(mv^2)
=0.5(0.20)(9)
=0.9 J
B) Determine the following for the COMBINED MASSES immediately AFTER the impact.
1. Its linear momentum:
p=(m1+m2)v
= (0.20+1.3)(3)
=4.5 kg*m/s
2. It's kinetic energy:
KE=0.5(m1+m2)(v^2)
=0.5(0.20+1.3)(9)
=6.75 J
After the collision, the two masses undergo simple harmonic motion about their position at impact.
C) Determine the amplitude of the harmonic motion.
I had no idea what to use for this?
D) Determine the period of the harmonic motion:
f=(1/2pi)*(sqrt(k/m1+m2))
T=1/f
=1/(1/2pi)*(sqrt(100/1.5))
=1/12.829 s
Any help on this is much appreciated!
A 0.20 kilogram mass is sliding on a horizontal, frictionless air track with a speed of 3.0 meters per second when it instantaneously hits and sticks to a 1.3 kilogram mass initially at rest on the track. The 1.3 kilogram mass is connected to one end of a massless spring, which has a spring constant of 100 Newtons per meter. The other end of the spring is fixed.
A) Determine the following for the 0.20 kilogram mass immediately BEFORE the impact.
1. Its linear momentum:
p=mv
= (0.20)(3)
=0.6 kg*m/s
2. It's kinetic energy:
KE=0.5(mv^2)
=0.5(0.20)(9)
=0.9 J
B) Determine the following for the COMBINED MASSES immediately AFTER the impact.
1. Its linear momentum:
p=(m1+m2)v
= (0.20+1.3)(3)
=4.5 kg*m/s
2. It's kinetic energy:
KE=0.5(m1+m2)(v^2)
=0.5(0.20+1.3)(9)
=6.75 J
After the collision, the two masses undergo simple harmonic motion about their position at impact.
C) Determine the amplitude of the harmonic motion.
I had no idea what to use for this?
D) Determine the period of the harmonic motion:
f=(1/2pi)*(sqrt(k/m1+m2))
T=1/f
=1/(1/2pi)*(sqrt(100/1.5))
=1/12.829 s
Any help on this is much appreciated!