A high diver jumping off a board (basic force problem)

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Homework Statement



A high diver of mass 50.0 kg jumps off a board 10.0 m above the water. If her downward motion is stopped 2.30 s after she enters the water, what average force did the water exert on her?


Homework Equations



Fnet=ma
vf2=v02+2ax

The Attempt at a Solution



First I found the final velocity of the diver when she hits the water

vf2=02+2(9.8)(10)=196

vf=14 m/s

Since she is slowed to a stop in 2.3s the average acceleration would be

14/2.3 = 6.08696

Knowing acceleration and her mass, we can calculate the force.

F=50(6.08696)=304.348

This answer was marked wrong. I'm pretty sure I did everything right. Am I missing something?
 
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Your calculation is correct for the magnitude of the acceleration. Maybe the dumb machine that marked this problem expected a negative sign in front of the acceleration. I say "dumb" because the acceleration is in the "up" direction which is conventionally positive. You may have to ask your teacher for a clarification of this point.
 
Thanks for your input, I'll be sure to ask my professor about this problem.