- #1
xhole
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Homework Statement
Hi all, i encounter this integral while i am trying to find the Fourier series of f(x)=ln(2*sin(x/2))
pi sin[(n+1/2)x] sin[(n-1/2)x]
∫ ------------- + ------------- dx n=1,2,3...
0 sin[(1/2)x] sin[(1/2)x]
Homework Equations
sin(A+B)=sinAcosB+sinBcosA
sin(2A)=2sinAcosA
The Attempt at a Solution
the answer seems to be 2*pi, but i still don't know how to work it out..