A integral consists of sin(n+1/2) n=1,2,3

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SUMMARY

The integral discussed involves the expression for Fourier series of the function f(x) = ln(2*sin(x/2)). The specific integral to evaluate is given by the formula: ∫(π sin[(n+1/2)x] / sin[(1/2)x]) + (π sin[(n-1/2)x] / sin[(1/2)x]) dx for n = 1, 2, 3. The solution is confirmed to be 2π, utilizing the properties of the Dirichlet Kernel for simplification.

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Homework Statement



Hi all, i encounter this integral while i am trying to find the Fourier series of f(x)=ln(2*sin(x/2))


pi sin[(n+1/2)x] sin[(n-1/2)x]
∫ ------------- + ------------- dx n=1,2,3...
0 sin[(1/2)x] sin[(1/2)x]


Homework Equations



sin(A+B)=sinAcosB+sinBcosA
sin(2A)=2sinAcosA

The Attempt at a Solution



the answer seems to be 2*pi, but i still don't know how to work it out..
 
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