A level physics doubt about a Diffraction grating

AI Thread Summary
Monochromatic light with a wavelength of 690 nm passes through a diffraction grating with 300 lines per mm, leading to a question about the maximum observable maxima. The relevant equation, n*wavelength = d*sin x, is provided, but the user struggles with determining the correct angle for calculations. Attempts to substitute values into the equation have not yielded the correct answer, indicating confusion about the problem. Additional context and effort in solving the problem are requested from the user to facilitate better assistance. The discussion highlights the importance of understanding the relationship between wavelength, grating spacing, and diffraction angles.
Atomsmasher2001
Messages
3
Reaction score
0

Homework Statement


Monochromatic light of wavelength 690nm passes through a diffraction grating with 300 lines per mm, producing a series of maxima on a screen. What is the greatest number of maximas that can be observed?
A) 4
B) 5
C) 8
D) 9

Homework Equations


n*wavelength = d*sin x

The Attempt at a Solution



Well, I took it as: wavelength= 690x10^-9 m
D = 300 x 10^-3 m
So I tried substituting in the equation but I didn’t know what angle to take. So yeah that’s where I’m stuck.[/B]
 
Last edited:
Physics news on Phys.org
What have you tried? Where exactly are you stuck?
 
renec112 said:
What have you tried? Where exactly are you stuck?

Well, I took it as: wavelength= 690x10^-9 m
D = 300 x 10^-3 m
So I tried substituting in the equation but I didn’t know what angle to take. So yeah that’s where I’m stuck.
 
@Atomsmasher2001 In general, please give us some more context in section two of the template and show more effort to solve the problem in section three. Usually you will have made some considerations, drawings or even calculations, so show them. I counted your previous post #3 as such an effort, although it lacks more than it shows.
 
fresh_42 said:
@Atomsmasher2001 In general, please give us some more context in section two of the template and show more effort to solve the problem in section three. Usually you will have made some considerations, drawings or even calculations, so show them. I counted your previous post #3 as such an effort, although it lacks more than it shows.
Ok sorry. But this is all the relevant formulas for this. My working I’ll show more. But I have no clue for this so I’m getting a completely wrong answer(not even close to the options).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top