A Person in Free Fall Newton's 2nd Law

[dacabbo]

A Person in "Free Fall" Newton's 2nd Law

Homework Statement

An 80kg aviator is in free fall and acquires a velocity of 60 m/s and then opens his parachute.
After falling an additional 30m, his velocity has been reduced to 20 m/s. What is the average acceleration of the aviator while his fall is being checked? What is the average force being exerted by the parachute?

Homework Equations

Force = Mass * acceleration
Average acceleration = change in velocity/change in time

The Attempt at a Solution

Any help would be appreciated, Dont understand how to go about problem

 

[HallsofIvy]

If a person has intial speed v_0 and constant acceleration a has, after time t, speed at+ v_0 and will have gone distance (a/2)t^2+ v_0t. So we will fall "an additional 30m" when (a/2)t^2+ 60t= 30. Solve the quadratic equation (a/2)t^2+ 60t- 30= 0for t. Of course, that will depend on a. Put that value of t into at+ 60= 20 and solve that equation for a.