A problem with a magnetic field and a revolving stick

AI Thread Summary
The discussion centers on solving a problem involving a stick revolving in a magnetic field, specifically calculating the induced voltage. The user initially struggles with applying Faraday's Law to determine the magnetic flux and the resulting electromotive force (EMF). Through community feedback, they clarify the need to include the angular velocity in their calculations for both the flux and its derivative. After addressing the confusion regarding units and incorporating the necessary elements, the user successfully arrives at the correct solution of 5 microvolts. The exchange highlights the importance of precise application of electromagnetic principles in problem-solving.
fara0815
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Helle there!
Elektrodynamics is giving me a hard time. I have been trying to figure the following question out by using textkooks like Haliday, Schaum's Outline and even my professor's script ;)
But unfortunately, I do not know how to solve it.

Problem:

A stick of length 0,1 m is revolving around one of its ends in a constant magnetic field of B=(0;0;1) mT. The stick's angular velocity is \omega=(0;0;1) s^1.
What is the voltage between the two ends?
(5 microV).

Since I have absolutely no clue, I would appreciate if someone could give me a hint where to start and lead me in a few steps to the result.

Many thanks in advance to this great community!
 
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You have probably already done the problem of finding the emf of a stick sliding on a rectangular loop of wire. Does that give you any ideas?
 
Let's see if I am getting close:

According to Faraday's Law, the magnetic flux is \phi_b= BA when B is normal to the surface A.
My problem here is that I first have to get the surface which the magnetic lines go through.
l=length of the stick
The surface of one radiant is A_{rad}=\frac{\pi l^2}{2\pi}=\frac{l^2}{2}
with that I get the surface related to the time:
A(t)=\frac{l^2\omega t}{2}

So the magnetic flux is
\phi_B=\frac{ Bl^2\omega t}{2}

And the EMF is
U_{ind}=\frac{\delta}{\delta t}\frac{ Bl^2\omega t}{2}=\frac{ Bl^2\omega}{2}= 0.05 microVolts

What am I missing? Is this even close?
 
Last edited:
fara0815 said:
Let's see if I am getting close:

According to Faraday's Law, the magnetic flux is \phi_b= BA when B is normal to the surface A.
My problem here is that I first have to get the surface which the magnetic lines go through.
l=length of the stick
The surface of one radiant is A_{rad}=\frac{\pi l^2}{2\pi}=\frac{l^2}{2}
with that I get the surface related to the time:
A(t)=\frac{l^2\omega t}{2}

So the magnetic flux is
\phi_B=\frac{ Bl^2\omegat}{2}

And the EMF is
U_{ind}=\frac{\delta}{\delta t}\frac{ Bl^2\omegat}{2}=\frac{ Bl^2\omega}{2}= 0.05 microVolts

What am I missing? Is this even close?
You are just missing the \omega t in a couple of places (flux and derivative of flux) but you got it back in the end.
 
latex was leaving them out. Now they are there. Sorry about that ;)
and I got confused by the units. But thank you very much for your help!
I am soo glad I finally figured it out! Right in time for the class tomorrow morning ;)
 
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