A question about forces on a mass

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The discussion focuses on determining the normal force acting on a mass at the lowest point of a curved inclined track. It highlights that the normal force is influenced by the curvature of the track, which introduces centripetal acceleration in addition to gravitational acceleration. The question arises whether the normal force differs from that of a mass placed directly at the bottom of the track due to the mass's prior acceleration down the incline. The consensus is that the curvature and the mass's previous motion do affect the normal force. Understanding these dynamics is crucial for accurately calculating the forces involved.
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The problem gives me a mass at the top of an inclined track. the track is not linear but curved and the bottom of the track is also curved such that mass m will leave the track in a "jump" My question lies, though, in that I want to know the force of the track on mass m when the mass is at the lowest point of the track (so the mass is essentially on a horizontal surface). In other words, the mass has been accelerating down the track and I want to know if this previous acceleration will effect the normal force. Is the normal force the same as if the mass had just been placed at the bottom of the track or is it different because the mass has been sliding down from height h?
 
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lightning208 said:
The problem gives me a mass at the top of an inclined track. the track is not linear but curved and the bottom of the track is also curved such that mass m will leave the track in a "jump" My question lies, though, in that I want to know the force of the track on mass m when the mass is at the lowest point of the track (so the mass is essentially on a horizontal surface). In other words, the mass has been accelerating down the track and I want to know if this previous acceleration will effect the normal force. Is the normal force the same as if the mass had just been placed at the bottom of the track or is it different because the mass has been sliding down from height h?

Hi lightning208! Welcome to PF! :smile:

The normal reaction force will be affected by the slope (which, as you say, is zero in this case), and by the curvature of the track, which causes a centripetal acceleration that has to be "added" to g. :smile:
 
thank you!
 
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