(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

an object having a mass of 25 kg is moving at a steady speed on ice. The coefficient of friction is 0.12.

a.) how much work is done moving the object 35 m?

b.) how much work is done if the object is accelerated at 0.55 m/s/s over a distance of 35 m?

2. Relevant equations

W=Fd Ff= mewFn F=ma

3. The attempt at a solution

a.)W= 0.12(25)(9.80)(35)

= 1029 J

b.) F= ma

= 25(0.55)

= 13.75 J

This is where i am confused, do i add up the work from part a to part be to get the total work? thanks

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# Homework Help: A question regarding work with friction

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