A river flows with a velocity of 3 m/s east

  • Thread starter Thread starter AimlessWander
  • Start date Start date
  • Tags Tags
    River Velocity
AI Thread Summary
To determine how far the boat moves downstream while crossing a 300 m wide river at 10 m/s north, first calculate the time to cross by dividing the width of the river by the boat's speed, resulting in 30 seconds. During this time, the river's current at 3 m/s east will push the boat downstream. Multiplying the current's speed by the crossing time gives a downstream displacement of 90 meters. Therefore, without correcting for the river flow, the boat will end up 90 meters downstream upon reaching the far shore. This calculation highlights the importance of considering river currents in navigation.
AimlessWander
Messages
15
Reaction score
0
A river flows with a velocity of 3 m/s east. The river is 300 m wide. A boat is moving 10 m/s due north. If the river flow is not corrected for, how far will the boat have moved downstream by the time is reaches the far shore?
 
Physics news on Phys.org
AimlessWander said:
A river flows with a velocity of 3 m/s east. The river is 300 m wide. A boat is moving 10 m/s due north. If the river flow is not corrected for, how far will the boat have moved downstream by the time is reaches the far shore?

You want to go to homework help for this kind of thing. I'll go ahead and give you a pointer since it's 3am and I doubt anyone else is awake:

Just look at your kinematics formulas.
1) Find the time it takes to cross the river at 10m/s, ignoring cross movement.
2) Then use that time value to see how far the boat will move downstream if it's going 3m/s.
 
Thank you :) Sorry, I just realized I posted in the wrong place.
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top