A shot fired from a gun with a muzzle velocity of 1200 ft per second is to hit a target 3000 feet away. Determine the minimum angle of elevation of the gun? Ok so I know that r(t)= (vcos(theta) t)i +(vsin(theta) t +16t^2)j I tried to set vcos(theta)t =3000, solve for t, and plug into the j component. However, I am getting confused with the math because i get t= 5/2cos(theta) and when I plug it in it gets pretty messed up. Can someone help?