A simple confusion: Showing projectile is launched horizontally

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Homework Help Overview

The discussion revolves around a projectile motion problem, specifically analyzing the trajectory of a ball described by the equation y = -0.05x^2. Participants are tasked with demonstrating that the ball is launched horizontally.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the angle of projection and the derivative of the trajectory equation. There are questions about the interpretation of the equation and the meaning of the derivative being zero.

Discussion Status

The discussion includes attempts to clarify the mathematical reasoning behind the angle of projection and its relationship to the trajectory. Some participants have provided insights into the derivative of the function, while others express confusion about the initial problem statement and the presence of the variable x.

Contextual Notes

There appears to be some missing information regarding the problem statement, which has led to confusion among participants. The discussion reflects varying levels of understanding about the mathematical concepts involved.

Faiq
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Member warned to use the homework template for posts in the homework sections of PF.
The equation of trajectory of ball B is y = -0.05x^2 where y is vertical displacement and x is horizontal. Prove that the ball is projected horizontallyFor this, the mark scheme says
x tan a = 0 so a =0
Since the angle between ball and surface is 0 the object is projected horizontally.
I can't work out how is x tan a = 0
 
Last edited:
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The problem statement got lost somehow.
 
Please check again
 
I don't see where the x would come from.

tan a is the derivative of your function at x=0. The derivative is 0, therefore tan a = 0.
 
How do you know the derivative is 0?
 
Got it thanks
 

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