A solid cylinder has a mass of

AI Thread Summary
A solid cylinder with a mass of 10 kg and a radius of 0.2 meters achieves a rotational velocity of 2 revolutions per second after 4 seconds, requiring a torque of 0.628 Nm. The user is confused about calculating the time it takes for the cylinder to rotate through its first 2π radians, which involves using the formula θ = 1/2(α*t^2). For part C, the user correctly applies the torque formula to find the force needed to pull the string, resulting in 3.14 N. Clarifications on the calculations for parts B and C are provided, emphasizing the correct application of rotational motion equations. Understanding these concepts is essential for solving the problem accurately.
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A solid cylinder has a mass of 10kg and a radius of .2 meters. Starting from rest it achieves a rotational velocity of 2 revolutions per second after 4 seconds.
a. What torque is required to cause this?
I found the Inertia, (.5)(10(.2) =.2 and found alpha= 2*2pi/4 and got 3.142. Then I took
.2(3.142) to find the Torque of .628Nm.

The problem I encounter is on part b.
B. How long did it take for the cylinder to rotate through its first 2pi radians?
I think it sounds rather basic but the question confuses me. Am I suppose to use the radius of .2 and the 3.142. I really don't know what is wanting me to do.

And then for part c.
C. Assuming this is produced by a string wound around the cylinder, how hard in Newtons, would the string have to be pulled?
I use the Torque formula again right? F*L? so i take like .628 and divide it by .2 to get 3.14N?

Those are my thoughts, great appreciation to anyone who can help me out! Thanks!
 
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For part B, what it is asking is how long it takes for the cylinder to rotate one full circle. That is what 2pi radians is.
 
B) Use theta=1/2(alpha*t^2), where theta = 2*3.142. Find t.
C) Torque = Force*radius. What you've written is correct.
 
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