A thin steel plate is in the shape of a half circle

AI Thread Summary
The discussion focuses on solving a homework problem involving a half steel plate with a radius of 4 meters and a surface density of (3+r) kg/m^2. Participants are tasked with calculating the area, mass, center of mass, and rotational inertia about specified axes using calculus. The area calculation is confirmed as 8π, while further assistance is requested for the remaining parts. The thread emphasizes the need for detailed attempts to facilitate help from others. Overall, the conversation revolves around applying calculus to determine various physical properties of the plate.
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Homework Statement


The half thin steel plate has a radius of 4 meters and a surface density of (3+r) kg/m^2, where r is the radial distance from the origin. Using calculus, find:
A. its area
B. its mass
C. Its center of mass with respect to the origin shown,
D. It's rotational inertia about the j axis
E. Its rotational inertia about an axis parallel to the j axis and passing through the center of mass.

Homework Equations


d=v0 t + (1/2)at^2
a=v^2 / r
v=v0 + at
v=dx/dt
a= dv/dt
σ = dm/dA φ = dm/dV
I = r^2 dm Ix+Iy = Iz
I = ICM + m k^2 (CM:center of mass subscript)
Discrete masses:
xCM = ∑mixi (CM:center of mass subscript)
i
-----------
∑mi
i
continuous mass distributions:
xCM = 1/M ∫x dm (CM:center of mass subscript)

The Attempt at a Solution


A. A= 1/2 pi R^2 =8pi
B.
C.
D.
E.
 

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Part A is right. Please show your attempts for the other parts if you want help.
 
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