A very weird improper integral on ^n

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Homework Statement


Verify that \int_{ℝ^n}exp(-\frac{λ}{2} \langle Ax, x \rangle-i \langle x,ζ \rangle )dx=(\frac{2\pi}{λ})^{\frac{1}{2}}(detA)^{-\frac{1}{2}}exp(-\frac{1}{2λ} \langle A^{-1}ζ, ζ \rangle ) where A is a symmetric matrix of complex numbers and <ReA x, x> is positive definite, and λ is a positive constant. ζ is a vector in ℝ^n

Homework Equations


Fubini's Theorem?

The Attempt at a Solution


The question is a lot easier if A is brought to diagonal form, so it is reasonable to make a change of variable that x= C y where C belongs to SO(n) such that C^-1 A C = B is diagonal. Since this change of variables means only geometrically a rotation of the R^n plane it should not change the range of values for integrating(still from -∞ to ∞). After this transformation we should be able to apply Fubini's Theorem and perform an iterated integration. But in the exponential function exp(-i\langle Cy, ζ \rangle) is still left to be dealt with and it doesn't come any where close that it could be of the form exp(-\frac{1}{2λ} \langle A^{-1}ζ, ζ \rangle) after integration as the answer suggests.. right now I'm trully stuck here.. Thanks for any help in advance!
 
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det A here means |det A| exp(i \sum_0^n{arg w_i}) where w is the eigenvalue of A.
This question even takes 20 minutes to type.. or I really suck at latex..
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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