About initial mass function and mean mass in stellar cluster

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SUMMARY

The discussion focuses on calculating the mass point in a stellar cluster using the Salpeter Initial Mass Function (IMF) with specified mass limits of 0.1 and 20 M⊙. The first calculation determines that the mass point at which half the mass lies in more massive systems is 0.5 M⊙. The equations used include fM = ∫xy M -7/3 M dM / ∫0.120 M -7/3 M dM, with a correction noted for the exponent in the second equation. This highlights the importance of precision in mathematical formulations when analyzing stellar mass distributions.

PREREQUISITES
  • Understanding of the Salpeter Initial Mass Function (IMF)
  • Familiarity with integral calculus
  • Knowledge of stellar mass limits (0.1 to 20 M⊙)
  • Ability to interpret astrophysical equations and their implications
NEXT STEPS
  • Study the implications of the Salpeter IMF on stellar evolution
  • Learn about the calculation of luminosity in star clusters
  • Explore advanced topics in stellar dynamics and mass distribution
  • Investigate the impact of different IMFs on star formation rates
USEFUL FOR

Astronomy students, astrophysicists, and researchers focusing on stellar formation and mass distribution in clusters will benefit from this discussion.

Cedric Chia
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Homework Statement


Assuming a Salpeter IMF with upper and lower mass limits of 0.1 and 20 M⊙ respectively, calculate:

(i) the mass point at which half the mass formed in a stellar cluster lies in more massive systems and half in less massive systems.

ii) the mass point at which half the luminosity of the star cluster lies in more massive systems and half in less massive systems.

Homework Equations


to find number of stars in the range x and y: fN = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM
to find mass occupied by the starts in the range x and y: fM = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM

The Attempt at a Solution


Question(i) :
using the second equation,
fM = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM
1/2 = ∫x20 M -7/3 dM / ∫0.120 M -7/3 dM
solving for x and we get,
x = 0.5 M⊙
 
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Your two relevant equations look the same but the exponent should be different.
 
mfb said:
Your two relevant equations look the same but the exponent should be different.
yess I'm really sorry I've forgot to put another M in the second equation!

correction:
to find mass occupied by the starts in the range x and y: fM = ∫xy M-7/3 M dM / ∫0.120 M-7/3 M dM
 

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