About mixed integral for perturbation in hydrogen atom

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SUMMARY

The discussion focuses on transforming the integral of the hydrogen atom perturbation from Cartesian to polar coordinates. The integral in question is modified from x²*exp(-r) to r*x²*exp(-r). Participants confirm that due to symmetry, the integrals of x²*exp(-r), y²*exp(-r), and z²*exp(-r) are equal, leading to the conclusion that the combined integral simplifies to r²*exp(-r). The transformation involves rewriting the differential volume element (dV) from Cartesian to polar coordinates.

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  • Understanding of quantum mechanics, specifically perturbation theory
  • Familiarity with integral calculus in both Cartesian and polar coordinates
  • Knowledge of the hydrogen atom model in quantum physics
  • Experience with symmetry principles in mathematical physics
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  • Learn about the symmetry properties of integrals in quantum systems
  • Explore the mathematical derivation of the hydrogen atom wave functions
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Homework Statement



During my calculation of hydrogen atom perturbation, I need to integral below in cartesian coordinate. It is given that below integral can be transformed.

Homework Equations



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Anyone could help to see what will the transformed integral in polar coordinate if the left-hand-side integral were changed to r*x^2*exp(-r) instead of x^2*exp(-r).

Thanks.

The Attempt at a Solution

 
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They are just using that the integral of x^2*exp(-r), y^2*exp(-r) and z^2*exp(-r) are all equal by symmetry. So if you add them all together you get r^2*exp(-r). Hence the '1/3'. Putting another r in front of x^2*exp(-r) doesn't stop you from doing the same thing.
 
Hi Dick, I just got it, and it only about rewriting dV in Cartesian to the polar coordinate.
Thanks for the help!
 

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