Absolute Value in a double integral

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SUMMARY

The discussion focuses on evaluating the double integral \(\int\int_{\Omega} \sqrt{|y-x^{2}|} dA\) over the region \(\Omega = [-1,1] \times [0,2]\). The integral requires splitting into two cases based on the condition of the absolute value: when \(x^{2} > y\) and when \(y > x^{2}\). The user initially struggled with determining the limits of integration but later resolved the issue independently.

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[SOLVED] Absolute Value in a double integral

Homework Statement



If \Omega = [-1,1] x [0,2], evaluate the double integral \int\int_{\Omega} \sqrt{|y-x^{2}|} dA given that it exists.

Homework Equations



None

The Attempt at a Solution



I know that in order to integrate with the absolute value I have to split the integral into two parts: When x^{2} > y ---> \sqrt{x^{2}-y} and y > x^{2} ---> \sqrt{y-x^{2}}

I just can't get of the limits of the integral. Anyone have any advice on where to start or how to look at it to discover the limits? TIA
 
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