A large boulder is ejected vertically upward from a volcano with an initial speed of 40.1 m/s. (Air resistance can be ignored.) a) At what time after being ejected is the boulder moving at 19.2 m/s upward? (g = 9.80 m/s^2) b) At what time is it moving at 19.2 m/s downward? (g = 9.80 m/s^2) c) When is the displacement of the boulder from its initial position zero? g = 9.80 m/s^2 d) When is the velocity of the boulder zero? g = 9.80 m/s^2 I did and understand these four parts. Now the following two parts are the ones I do not understand. e) What is the magnitude of the acceleration while the boulder is moving? (Take g = 9.80 m/s^2 for free fall acceleration) Well, the boulder can move up or down, but is the magnitude 9.80 m/s^2 for both scenarios? f. What is the direction, up or down, of the acceleration while the boulder is moving? Won't the direction be down? Thanks for any help.