Acceleration of an electron in a constant electric field

AI Thread Summary
An electron starting from rest is accelerated by a uniform electric field of 4 x 10^4 N/C over a distance of 7 cm. To find the speed of the electron after exiting the field, the work-energy theorem is applicable, which relates work done to kinetic energy. The force on the electron can be calculated using the electric field strength and the charge of the electron. The work done on the electron can then be determined, allowing for the calculation of its final speed. Understanding these principles is crucial for solving the problem effectively.
gc33550
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Homework Statement


An electron, starting from rest, is accelerated by a uniform electric field of 4 104 N/C that extends over a distance of 7 cm. Find the speed of the electron after it leaves the region of uniform electric field.


Homework Equations


F=(q1q2)/r^2
and maybe the Work equation


The Attempt at a Solution


I really have no idea if i could get an idea of how to start it i may be able to think through it. I don't want an answer just a little guidance please
 
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The work-energy theorem is the way to go ...
 
2. Homework Equations
F=(q1q2)/r^2
and maybe the Work equation

Your force equation is incorrect; You are missing a constant
 
gc33550 said:

Homework Statement


An electron, starting from rest, is accelerated by a uniform electric field of 4 104 N/C that extends over a distance of 7 cm. Find the speed of the electron after it leaves the region of uniform electric field.


Homework Equations


F=(q1q2)/r^2
and maybe the Work equation
What is the force experienced by an electron in an electric field?
What is the work done on the electron by the electric field?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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