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Acceleration of gravity at pendulum

  • Thread starter Aamun
  • Start date
10
0
1. The problem statement, all variables and given/known data
A pendulum which is 2.00m long makes 84.5 complete oscillations in 4.00 min. What is the acceleration of gravity at that spot? Show all work and formulas.


2. Relevant equations

T=2(3.14) SQRT(l/g)

3. The attempt at a solution

L= g*(T/2pi)^2
2.00=g*(4.00/6.28)^2
g=4.9298 m/s

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I'm not sure if i'm missing a step, or if this is correct.. which is where I run into the problem. I'm also not sure of where the Oscillations would fit in.
 

nicksauce

Science Advisor
Homework Helper
1,272
5
T is the number of seconds per oscillation. You can figure this out with the data given.
 
10
0
So it would be 4/84.5= 0.047 minutes per oscillation = 2.84 oscillations per second?
 
Last edited:

nicksauce

Science Advisor
Homework Helper
1,272
5
2.84 seconds per oscillation, yes.
 
If you're trying to find g, wouldn't it be easier to solve the equation for g immediately? But that's not the main problem. The 4 mins is not T, it is the time it takes for 84.5 oscillations, not 1.

EDIT: lol sorry too late :D
 
10
0
Ok, I got it, thanks a bunch! =)
 

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