Acceleration of System of Objects w/ m1=10kg, m2=20kg

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The discussion focuses on calculating the acceleration of a system involving two masses, m1 = 10 kg and m2 = 20 kg, on an incline with angles θ = 60° and φ = 30°. The equations used include tension and Newton's second law, leading to a total tension calculation of T_total = 223.2 N. The net force acting on the system is determined to be F = 123.21 N, resulting in an acceleration of a = 4.11 m/s². Participants suggest drawing free body diagrams for clarity and applying Newton's laws to derive the acceleration accurately.
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Homework Statement




Find the acceleration of the system of two masses shown in the figure, given that m1 = 10 kg, m2 = 20 kg, θ = 60o and φ = 30o. Assume that the incline plane is smooth (i.e., there is no friction) and that g = 10 m/s2.


Homework Equations


A: T=m_{2}g*sinθ + m_{1}g*sinφ
B: T_{1}=T_{2}
C: F=ma

The Attempt at a Solution


T_{total}=223.2 using A
-----
F=m_{2}g*sinθ - m_{1}g*sinφ

F=123.21
-----
Using C: a=F/m
a=m_{2}g*sinθ - m_{1}g*sinφ / m_{1} + m_{2}
a= 4.11m/s^{2}



I'm not sure how to approach this one...
I know tension = T_{1}=T_{2}...
Then i get the Force that will be going right since m_{1} < m_{2}
and find the acceleration. I just want someone to see if I understood this right.
I was trying to approach the masses as two different components, but it didn't work that well..
 

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Nanoath said:

Homework Equations


A: T=m_{2}g*sinθ + m_{1}g*sinφ
Where did you get this equation?
B: T_{1}=T_{2}
C: F=ma
These make sense.

Do this: Draw a free body diagram for each mass, showing all forces acting. Then apply Newton's 2nd law (your equation C) to each mass. Combine the two equations to solve for the acceleration.
 
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