# Acceleration problem

## Homework Statement

A sports car accelerates from rest to 100km/hr in 6.2s. What is it's acceleration in m/s^2?

## The Attempt at a Solution

I converted the 100 km/hr to m/s and got 16.7 m/s. I think that the formula that I am supposed to use is Vf-Vo/t. I don't know what to do next or if even what I did is correct.

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dlgoff
Gold Member
100 km/hr=(100x1000)meter/60min=(100x1000)meter/(60x60)sec=27.8meter/sec.

Now look at the units for acceleration. This should tell you what you must do with velocity(m/s) to get m/s^2.

100 kM/hr = 27.78 m/s not 16.7 m/s. Look in your book. You should find a reference equation that looks something like v=at+vo. Since you know v0=o at time=0 the equation becomes simple. Now solve for acceleration since you have been given both the time and final velocity.

Hope this helps.

since 100km/h = 27.8 m/s

use v^2 = V0^2 + 2a(y-y0)

27.8^2 = 0 + 2a(y) ; 2 unknowns
/////(27.8^2) / 2a = y

then use y = y0+v0T+.5aT^2
plug in with the Y you solved for in the other equation.
772.84 / 2a = 0 + 0T + .5aT^2
remember t = 6.2
solve for a; a = 4.48 m/s^2

check my math, i dont know

Last edited:
dlgoff
Gold Member
since 100km/h = 27.8 m/s

use v^2 = V0^2 + 2a(y-y0)

27.8^2 = 0 + 2a(y) ; 2 unknowns
/////(27.8^2) / 2a = y

then use y = y0+v0T+.5aT^2
plug in with the Y you solved for in the other equation.
772.84 / 2a = 0 + 0T + .5aT^2
t = 6.2
solve for a; a = 4.48 m/s^2

check my math, i dont know
You are making it too complicated. You have one equation with one unknown: v=at+vo

I'm not sure if I exactly understand. I understand a little more than I did before. It is hard for me because my class does not use a book and we have one practice problem as our notes.

Last edited:
dlgoff